IMPORTANT PERCENTAGE PROBLEM CONCEPTS SHORTCUT TRICKS FOR COMPETITIVE EXAM
(Q1)If Ravi salary is 25 % more than Raju’s salary the percentage by which Raju’s salary is less then Ravi salary.
Solution: BY TRICK
Required percentage=(25/100+25)×100)
(Q2)If A’s income is 50% less than that of B’s, then B’s income is what percent more than that of A?
Solution: BY TRICK
Required percentage:(50/100−50)×100
=(50/50)×100
=100% Ans
(Q3)Two numbers are more than the third number by 20% and 50% respectively. The first number is what percent of the second number?
Solution: Let third number=100
First number=120
Second number=150
∴ Required percentage=(120/150)×100
=80% Ans.
BY TRICK:
∴ Required percentage=(100+20/100+50)×100
=80% Ans.
(Q4)Two numbers are less than a third number by 30% and 37% respectively.The percent by which the second number is less than the first is.
Solution: Let the third number=100
First number=70
Second number=63
∴ Required percentage=(7/70)×100
=10% Ans.
(Q5)Two numbers are respectively 20% and 50% more than a third number. the ratio of the two numbers is.
Solution: Let the third number=100
First number=120
Second number=150
∴ Required ratio=120/150
=4/5
=4:5 Ans.
(Q6)25% of the annual salary of A is equal to 80% of the annual salary of the B.Monthly salary of B is 40% of the monthly salary of the C.Annual salary of C is Rs. 6 lac. what is the monthly salary of A?
Solution: monthly salary of C=600000/12
=Rs 50000
B’s monthly salary=(50000×40)/100
=Rs 20000
Annual salary of B=20000×12
=240000
Now,
Let Annual salary of A=X
( X×25)/100=(240000×80)/100
=>25X = 240000×80
∴ X=(240000×80)/25
=Rs 768000
monthly salary of A=768000/12
=Rs 64000 Ans.
(Q7)The monthly salaries of A and B together amount to Rs 40,000.A spends 85% of his salary and B, 95% of his salary.if now their saving is the same, then the salary(in Rs) of A is.
Solution: Let salary of A=X
salary of B=40000−X
Saving of A=15%
Saving of B=5%
Now according to question their saving are same so
( X×15)/100=(40000−X)×5/100
=>15X=200000−5X
=>20X=200000
∴ X=Rs 10000 Ans.
(Q8)Mohan donated 3% of his income to a charity and deposited 12% of the rest in the bank.if now he has Rs.12804, then his income was.
Solution:
Let income=100x
Now,
85.36x=12804
∴ x=150
income=100x
=100×150
=Rs 15000 Ans.
Rough:
(100x×3)/100=3x
rest=100x-3x=97x
deposit=12% of rest i.e 97x
(97x×12)/100
=11.64x
remaining=97x−11.64x=85.36x
(Q9)Mohan saves 14% of his salary while Shyam saves 22%. if both get the same salary and Shyam saves Rs. 1540, what is the saving of Mohan?
Solution: According to question Shyam saves 22% i.e equal to 1540
now,
22%=1540
∴ 1%=1540/22
∴100%=(1540/22)×100
=Rs 7000 salaries of Shyam
saving of ram=(7000×14)/100
=Rs.980 Ans.